If an available roof area is 12m² and the PV system has an efficiency of 15%, how much photovoltaic capacity can fit on it?

Prepare for the NABCEP PV Associate Exam. Utilize flashcards and multiple-choice questions with detailed explanations. Get equipped for your solar energy certification!

To determine the photovoltaic capacity that can fit on a roof area of 12 m² with a system efficiency of 15%, you can use the formula for calculating the capacity of the PV system as follows:

Capacity (kW) = Available Roof Area (m²) × Efficiency × Solar Irradiance (kW/m²)

For solar irradiance, a common standard value is approximately 1 kW/m², which reflects peak sunlight conditions.

Now, if we substitute the values into the formula:

  1. Available Roof Area: 12 m²
  2. Efficiency: 15% or 0.15 (as a fraction)

Using the standard solar irradiance value:

Capacity = 12 m² × 0.15 × 1 kW/m²

Calculating this gives:

Capacity = 12 × 0.15 = 1.8 kW

This means that under ideal conditions, a PV system with an efficiency of 15% can generate a capacity of 1.8 kW on a roof area of 12 m². Thus, the choice indicating 1.8 kW accurately represents the potential output considering the available data.

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