What is the monthly energy use of an off-grid installation with a 1HP pump operating 10% of the time and a 20W light operating 100% of the time?

Prepare for the NABCEP PV Associate Exam. Utilize flashcards and multiple-choice questions with detailed explanations. Get equipped for your solar energy certification!

Multiple Choice

What is the monthly energy use of an off-grid installation with a 1HP pump operating 10% of the time and a 20W light operating 100% of the time?

Explanation:
To determine the monthly energy use of the off-grid installation, we first need to calculate the energy consumption of both the 1HP pump and the 20W light over the course of a month. Start with the pump. A 1 horsepower (HP) pump is equivalent to approximately 746 watts. If the pump operates 10% of the time in a month, we can calculate its monthly energy use as follows: 1. Convert the percentage of operation to hours: - A month typically has about 720 hours (30 days x 24 hours). - 10% of 720 hours is 72 hours. 2. Calculate the energy consumed by the pump: - Energy (kWh) = Power (kW) x Time (h) - In this case, 746 watts = 0.746 kW, so: - Energy = 0.746 kW x 72 h = 53.712 kWh. Next, consider the 20W light that operates 100% of the time. The energy consumption calculation is straightforward because it runs continuously: 1. Energy consumed by the light over the month: - 20 watts = 0.02 kW. -

To determine the monthly energy use of the off-grid installation, we first need to calculate the energy consumption of both the 1HP pump and the 20W light over the course of a month.

Start with the pump. A 1 horsepower (HP) pump is equivalent to approximately 746 watts. If the pump operates 10% of the time in a month, we can calculate its monthly energy use as follows:

  1. Convert the percentage of operation to hours:
  • A month typically has about 720 hours (30 days x 24 hours).

  • 10% of 720 hours is 72 hours.

  1. Calculate the energy consumed by the pump:
  • Energy (kWh) = Power (kW) x Time (h)

  • In this case, 746 watts = 0.746 kW, so:

  • Energy = 0.746 kW x 72 h = 53.712 kWh.

Next, consider the 20W light that operates 100% of the time. The energy consumption calculation is straightforward because it runs continuously:

  1. Energy consumed by the light over the month:
  • 20 watts = 0.02 kW.

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy